Adam has some paint.
He uses
59 of it to paint 8 gates and 3 chairs.
The amount of paint needed to paint a chair is 4 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
8 |
3 |
Value |
1 u |
4 u |
Total value |
8 u |
12 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 4 u
Paint needed for 8 gates and 3 chairs
= 8 x 1 u x 3 x 4 u
= 8 u + 12 u
= 20 u
59 of the paint = 20 u
19 of the paint = 20 u ÷ 5 = 4 u
Fraction of the remaining paint left
= 1 -
59=
49 49 of the paint = 4 x 4 u = 16 u
Remaining paint left = 16 u
Number of gates that Adam can paint with the remaining paint
= 16 u ÷ 1 u
= 16
(b)
Number of chairs that Adam can paint with the remaining paint
= 16 u ÷ 4 u
= 4
Answer(s): (a) 16; (b) 4