Adam has some paint.
He uses
511 of it to paint 7 doors and 4 gates.
The amount of paint needed to paint a gate is 2 times that of a door.
- How many doors can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Doors |
Gates |
Number |
7 |
4 |
Value |
1 u |
2 u |
Total value |
7 u |
8 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 7 doors and 4 gates
= 7 x 1 u x 4 x 2 u
= 7 u + 8 u
= 15 u
511 of the paint = 15 u
111 of the paint = 15 u ÷ 5 = 3 u
Fraction of the remaining paint left
= 1 -
511=
611 611 of the paint = 6 x 3 u = 18 u
Remaining paint left = 18 u
Number of doors that Adam can paint with the remaining paint
= 18 u ÷ 1 u
= 18
(b)
Number of gates that Adam can paint with the remaining paint
= 18 u ÷ 2 u
= 9
Answer(s): (a) 18; (b) 9