Adam has some paint.
He uses
310 of it to paint 4 chairs and 7 gates.
The amount of paint needed to paint a gate is 2 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Chairs |
Gates |
Number |
4 |
7 |
Value |
1 u |
2 u |
Total value |
4 u |
14 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 4 chairs and 7 gates
= 4 x 1 u x 7 x 2 u
= 4 u + 14 u
= 18 u
310 of the paint = 18 u
110 of the paint = 18 u ÷ 3 = 6 u
Fraction of the remaining paint left
= 1 -
310=
710 710 of the paint = 7 x 6 u = 42 u
Remaining paint left = 42 u
Number of chairs that Adam can paint with the remaining paint
= 42 u ÷ 1 u
= 42
(b)
Number of gates that Adam can paint with the remaining paint
= 42 u ÷ 2 u
= 21
Answer(s): (a) 42; (b) 21