Adam has some paint.
He uses
311 of it to paint 10 doors and 7 chairs.
The amount of paint needed to paint a chair is 5 times that of a door.
- How many doors can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Doors |
Chairs |
Number |
10 |
7 |
Value |
1 u |
5 u |
Total value |
10 u |
35 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 chair = 5 u
Paint needed for 10 doors and 7 chairs
= 10 x 1 u x 7 x 5 u
= 10 u + 35 u
= 45 u
311 of the paint = 45 u
111 of the paint = 45 u ÷ 3 = 15 u
Fraction of the remaining paint left
= 1 -
311=
811 811 of the paint = 8 x 15 u = 120 u
Remaining paint left = 120 u
Number of doors that Adam can paint with the remaining paint
= 120 u ÷ 1 u
= 120
(b)
Number of chairs that Adam can paint with the remaining paint
= 120 u ÷ 5 u
= 24
Answer(s): (a) 120; (b) 24