Adam has some paint.
He uses
23 of it to paint 6 gates and 10 doors.
The amount of paint needed to paint a door is 3 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Gates |
Doors |
Number |
6 |
10 |
Value |
1 u |
3 u |
Total value |
6 u |
30 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 door = 3 u
Paint needed for 6 gates and 10 doors
= 6 x 1 u x 10 x 3 u
= 6 u + 30 u
= 36 u
23 of the paint = 36 u
13 of the paint = 36 u ÷ 2 = 18 u
Fraction of the remaining paint left
= 1 -
23=
13 13 of the paint = 1 x 18 u = 18 u
Remaining paint left = 18 u
Number of gates that Adam can paint with the remaining paint
= 18 u ÷ 1 u
= 18
(b)
Number of doors that Adam can paint with the remaining paint
= 18 u ÷ 3 u
= 6
Answer(s): (a) 18; (b) 6