Adam has some paint.
He uses
49 of it to paint 4 tables and 10 gates.
The amount of paint needed to paint a gate is 2 times that of a table.
- How many tables can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Tables |
Gates |
Number |
4 |
10 |
Value |
1 u |
2 u |
Total value |
4 u |
20 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 4 tables and 10 gates
= 4 x 1 u x 10 x 2 u
= 4 u + 20 u
= 24 u
49 of the paint = 24 u
19 of the paint = 24 u ÷ 4 = 6 u
Fraction of the remaining paint left
= 1 -
49=
59 59 of the paint = 5 x 6 u = 30 u
Remaining paint left = 30 u
Number of tables that Adam can paint with the remaining paint
= 30 u ÷ 1 u
= 30
(b)
Number of gates that Adam can paint with the remaining paint
= 30 u ÷ 2 u
= 15
Answer(s): (a) 30; (b) 15