Adam has some paint.
He uses
34 of it to paint 10 doors and 4 tables.
The amount of paint needed to paint a table is 2 times that of a door.
- How many doors can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Doors |
Tables |
Number |
10 |
4 |
Value |
1 u |
2 u |
Total value |
10 u |
8 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 table = 2 u
Paint needed for 10 doors and 4 tables
= 10 x 1 u x 4 x 2 u
= 10 u + 8 u
= 18 u
34 of the paint = 18 u
14 of the paint = 18 u ÷ 3 = 6 u
Fraction of the remaining paint left
= 1 -
34=
14 14 of the paint = 1 x 6 u = 6 u
Remaining paint left = 6 u
Number of doors that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of tables that Adam can paint with the remaining paint
= 6 u ÷ 2 u
= 3
Answer(s): (a) 6; (b) 3