Adam has some paint.
He uses
23 of it to paint 8 chairs and 4 tables.
The amount of paint needed to paint a table is 2 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Chairs |
Tables |
Number |
8 |
4 |
Value |
1 u |
2 u |
Total value |
8 u |
8 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 table = 2 u
Paint needed for 8 chairs and 4 tables
= 8 x 1 u x 4 x 2 u
= 8 u + 8 u
= 16 u
23 of the paint = 16 u
13 of the paint = 16 u ÷ 2 = 8 u
Fraction of the remaining paint left
= 1 -
23=
13 13 of the paint = 1 x 8 u = 8 u
Remaining paint left = 8 u
Number of chairs that Adam can paint with the remaining paint
= 8 u ÷ 1 u
= 8
(b)
Number of tables that Adam can paint with the remaining paint
= 8 u ÷ 2 u
= 4
Answer(s): (a) 8; (b) 4