Adam has some paint.
He uses
56 of it to paint 8 gates and 6 doors.
The amount of paint needed to paint a door is 2 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Gates |
Doors |
Number |
8 |
6 |
Value |
1 u |
2 u |
Total value |
8 u |
12 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 door = 2 u
Paint needed for 8 gates and 6 doors
= 8 x 1 u x 6 x 2 u
= 8 u + 12 u
= 20 u
56 of the paint = 20 u
16 of the paint = 20 u ÷ 5 = 4 u
Fraction of the remaining paint left
= 1 -
56=
16 16 of the paint = 1 x 4 u = 4 u
Remaining paint left = 4 u
Number of gates that Adam can paint with the remaining paint
= 4 u ÷ 1 u
= 4
(b)
Number of doors that Adam can paint with the remaining paint
= 4 u ÷ 2 u
= 2
Answer(s): (a) 4; (b) 2