Adam has some paint.
He uses
45 of it to paint 10 gates and 7 doors.
The amount of paint needed to paint a door is 2 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Gates |
Doors |
Number |
10 |
7 |
Value |
1 u |
2 u |
Total value |
10 u |
14 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 door = 2 u
Paint needed for 10 gates and 7 doors
= 10 x 1 u x 7 x 2 u
= 10 u + 14 u
= 24 u
45 of the paint = 24 u
15 of the paint = 24 u ÷ 4 = 6 u
Fraction of the remaining paint left
= 1 -
45=
15 15 of the paint = 1 x 6 u = 6 u
Remaining paint left = 6 u
Number of gates that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of doors that Adam can paint with the remaining paint
= 6 u ÷ 2 u
= 3
Answer(s): (a) 6; (b) 3