Adam has some paint.
He uses
57 of it to paint 9 chairs and 7 tables.
The amount of paint needed to paint a table is 3 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Chairs |
Tables |
Number |
9 |
7 |
Value |
1 u |
3 u |
Total value |
9 u |
21 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 table = 3 u
Paint needed for 9 chairs and 7 tables
= 9 x 1 u x 7 x 3 u
= 9 u + 21 u
= 30 u
57 of the paint = 30 u
17 of the paint = 30 u ÷ 5 = 6 u
Fraction of the remaining paint left
= 1 -
57=
27 27 of the paint = 2 x 6 u = 12 u
Remaining paint left = 12 u
Number of chairs that Adam can paint with the remaining paint
= 12 u ÷ 1 u
= 12
(b)
Number of tables that Adam can paint with the remaining paint
= 12 u ÷ 3 u
= 4
Answer(s): (a) 12; (b) 4