Adam has some paint.
He uses
35 of it to paint 8 tables and 7 doors.
The amount of paint needed to paint a door is 4 times that of a table.
- How many tables can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Tables |
Doors |
Number |
8 |
7 |
Value |
1 u |
4 u |
Total value |
8 u |
28 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 door = 4 u
Paint needed for 8 tables and 7 doors
= 8 x 1 u x 7 x 4 u
= 8 u + 28 u
= 36 u
35 of the paint = 36 u
15 of the paint = 36 u ÷ 3 = 12 u
Fraction of the remaining paint left
= 1 -
35=
25 25 of the paint = 2 x 12 u = 24 u
Remaining paint left = 24 u
Number of tables that Adam can paint with the remaining paint
= 24 u ÷ 1 u
= 24
(b)
Number of doors that Adam can paint with the remaining paint
= 24 u ÷ 4 u
= 6
Answer(s): (a) 24; (b) 6