Adam has some paint.
He uses
57 of it to paint 3 tables and 6 chairs.
The amount of paint needed to paint a chair is 2 times that of a table.
- How many tables can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Tables |
Chairs |
Number |
3 |
6 |
Value |
1 u |
2 u |
Total value |
3 u |
12 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 chair = 2 u
Paint needed for 3 tables and 6 chairs
= 3 x 1 u x 6 x 2 u
= 3 u + 12 u
= 15 u
57 of the paint = 15 u
17 of the paint = 15 u ÷ 5 = 3 u
Fraction of the remaining paint left
= 1 -
57=
27 27 of the paint = 2 x 3 u = 6 u
Remaining paint left = 6 u
Number of tables that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of chairs that Adam can paint with the remaining paint
= 6 u ÷ 2 u
= 3
Answer(s): (a) 6; (b) 3