Adam has some paint.
He uses
38 of it to paint 6 doors and 4 chairs.
The amount of paint needed to paint a chair is 3 times that of a door.
- How many doors can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Doors |
Chairs |
Number |
6 |
4 |
Value |
1 u |
3 u |
Total value |
6 u |
12 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 6 doors and 4 chairs
= 6 x 1 u x 4 x 3 u
= 6 u + 12 u
= 18 u
38 of the paint = 18 u
18 of the paint = 18 u ÷ 3 = 6 u
Fraction of the remaining paint left
= 1 -
38=
58 58 of the paint = 5 x 6 u = 30 u
Remaining paint left = 30 u
Number of doors that Adam can paint with the remaining paint
= 30 u ÷ 1 u
= 30
(b)
Number of chairs that Adam can paint with the remaining paint
= 30 u ÷ 3 u
= 10
Answer(s): (a) 30; (b) 10