Adam has some paint.
He uses
38 of it to paint 6 chairs and 9 doors.
The amount of paint needed to paint a door is 5 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Chairs |
Doors |
Number |
6 |
9 |
Value |
1 u |
5 u |
Total value |
6 u |
45 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 door = 5 u
Paint needed for 6 chairs and 9 doors
= 6 x 1 u x 9 x 5 u
= 6 u + 45 u
= 51 u
38 of the paint = 51 u
18 of the paint = 51 u ÷ 3 = 17 u
Fraction of the remaining paint left
= 1 -
38=
58 58 of the paint = 5 x 17 u = 85 u
Remaining paint left = 85 u
Number of chairs that Adam can paint with the remaining paint
= 85 u ÷ 1 u
= 85
(b)
Number of doors that Adam can paint with the remaining paint
= 85 u ÷ 5 u
= 17
Answer(s): (a) 85; (b) 17