Adam has some paint.
He uses
34 of it to paint 6 gates and 10 chairs.
The amount of paint needed to paint a chair is 3 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
6 |
10 |
Value |
1 u |
3 u |
Total value |
6 u |
30 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 6 gates and 10 chairs
= 6 x 1 u x 10 x 3 u
= 6 u + 30 u
= 36 u
34 of the paint = 36 u
14 of the paint = 36 u ÷ 3 = 12 u
Fraction of the remaining paint left
= 1 -
34=
14 14 of the paint = 1 x 12 u = 12 u
Remaining paint left = 12 u
Number of gates that Adam can paint with the remaining paint
= 12 u ÷ 1 u
= 12
(b)
Number of chairs that Adam can paint with the remaining paint
= 12 u ÷ 3 u
= 4
Answer(s): (a) 12; (b) 4