Adam has some paint.
He uses
511 of it to paint 8 doors and 4 chairs.
The amount of paint needed to paint a chair is 3 times that of a door.
- How many doors can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Doors |
Chairs |
Number |
8 |
4 |
Value |
1 u |
3 u |
Total value |
8 u |
12 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 8 doors and 4 chairs
= 8 x 1 u x 4 x 3 u
= 8 u + 12 u
= 20 u
511 of the paint = 20 u
111 of the paint = 20 u ÷ 5 = 4 u
Fraction of the remaining paint left
= 1 -
511=
611 611 of the paint = 6 x 4 u = 24 u
Remaining paint left = 24 u
Number of doors that Adam can paint with the remaining paint
= 24 u ÷ 1 u
= 24
(b)
Number of chairs that Adam can paint with the remaining paint
= 24 u ÷ 3 u
= 8
Answer(s): (a) 24; (b) 8