Adam has some paint.
He uses
35 of it to paint 2 doors and 5 tables.
The amount of paint needed to paint a table is 2 times that of a door.
- How many doors can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Doors |
Tables |
Number |
2 |
5 |
Value |
1 u |
2 u |
Total value |
2 u |
10 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 table = 2 u
Paint needed for 2 doors and 5 tables
= 2 x 1 u x 5 x 2 u
= 2 u + 10 u
= 12 u
35 of the paint = 12 u
15 of the paint = 12 u ÷ 3 = 4 u
Fraction of the remaining paint left
= 1 -
35=
25 25 of the paint = 2 x 4 u = 8 u
Remaining paint left = 8 u
Number of doors that Adam can paint with the remaining paint
= 8 u ÷ 1 u
= 8
(b)
Number of tables that Adam can paint with the remaining paint
= 8 u ÷ 2 u
= 4
Answer(s): (a) 8; (b) 4