Adam has some paint.
He uses
310 of it to paint 5 tables and 2 chairs.
The amount of paint needed to paint a chair is 5 times that of a table.
- How many tables can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Tables |
Chairs |
Number |
5 |
2 |
Value |
1 u |
5 u |
Total value |
5 u |
10 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 chair = 5 u
Paint needed for 5 tables and 2 chairs
= 5 x 1 u x 2 x 5 u
= 5 u + 10 u
= 15 u
310 of the paint = 15 u
110 of the paint = 15 u ÷ 3 = 5 u
Fraction of the remaining paint left
= 1 -
310=
710 710 of the paint = 7 x 5 u = 35 u
Remaining paint left = 35 u
Number of tables that Adam can paint with the remaining paint
= 35 u ÷ 1 u
= 35
(b)
Number of chairs that Adam can paint with the remaining paint
= 35 u ÷ 5 u
= 7
Answer(s): (a) 35; (b) 7