Adam has some paint.
He uses
23 of it to paint 6 doors and 3 gates.
The amount of paint needed to paint a gate is 2 times that of a door.
- How many doors can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Doors |
Gates |
Number |
6 |
3 |
Value |
1 u |
2 u |
Total value |
6 u |
6 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 6 doors and 3 gates
= 6 x 1 u x 3 x 2 u
= 6 u + 6 u
= 12 u
23 of the paint = 12 u
13 of the paint = 12 u ÷ 2 = 6 u
Fraction of the remaining paint left
= 1 -
23=
13 13 of the paint = 1 x 6 u = 6 u
Remaining paint left = 6 u
Number of doors that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of gates that Adam can paint with the remaining paint
= 6 u ÷ 2 u
= 3
Answer(s): (a) 6; (b) 3