Adam has some paint.
He uses
34 of it to paint 9 tables and 3 chairs.
The amount of paint needed to paint a chair is 3 times that of a table.
- How many tables can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Tables |
Chairs |
Number |
9 |
3 |
Value |
1 u |
3 u |
Total value |
9 u |
9 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 9 tables and 3 chairs
= 9 x 1 u x 3 x 3 u
= 9 u + 9 u
= 18 u
34 of the paint = 18 u
14 of the paint = 18 u ÷ 3 = 6 u
Fraction of the remaining paint left
= 1 -
34=
14 14 of the paint = 1 x 6 u = 6 u
Remaining paint left = 6 u
Number of tables that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of chairs that Adam can paint with the remaining paint
= 6 u ÷ 3 u
= 2
Answer(s): (a) 6; (b) 2