Adam has some paint.
He uses
79 of it to paint 6 chairs and 2 tables.
The amount of paint needed to paint a table is 4 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Chairs |
Tables |
Number |
6 |
2 |
Value |
1 u |
4 u |
Total value |
6 u |
8 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 table = 4 u
Paint needed for 6 chairs and 2 tables
= 6 x 1 u x 2 x 4 u
= 6 u + 8 u
= 14 u
79 of the paint = 14 u
19 of the paint = 14 u ÷ 7 = 2 u
Fraction of the remaining paint left
= 1 -
79=
29 29 of the paint = 2 x 2 u = 4 u
Remaining paint left = 4 u
Number of chairs that Adam can paint with the remaining paint
= 4 u ÷ 1 u
= 4
(b)
Number of tables that Adam can paint with the remaining paint
= 4 u ÷ 4 u
= 1
Answer(s): (a) 4; (b) 1