Adam has some paint.
He uses
311 of it to paint 5 chairs and 8 gates.
The amount of paint needed to paint a gate is 2 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Chairs |
Gates |
Number |
5 |
8 |
Value |
1 u |
2 u |
Total value |
5 u |
16 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 5 chairs and 8 gates
= 5 x 1 u x 8 x 2 u
= 5 u + 16 u
= 21 u
311 of the paint = 21 u
111 of the paint = 21 u ÷ 3 = 7 u
Fraction of the remaining paint left
= 1 -
311=
811 811 of the paint = 8 x 7 u = 56 u
Remaining paint left = 56 u
Number of chairs that Adam can paint with the remaining paint
= 56 u ÷ 1 u
= 56
(b)
Number of gates that Adam can paint with the remaining paint
= 56 u ÷ 2 u
= 28
Answer(s): (a) 56; (b) 28