Adam has some paint.
He uses
38 of it to paint 9 chairs and 3 doors.
The amount of paint needed to paint a door is 5 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Chairs |
Doors |
Number |
9 |
3 |
Value |
1 u |
5 u |
Total value |
9 u |
15 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 door = 5 u
Paint needed for 9 chairs and 3 doors
= 9 x 1 u x 3 x 5 u
= 9 u + 15 u
= 24 u
38 of the paint = 24 u
18 of the paint = 24 u ÷ 3 = 8 u
Fraction of the remaining paint left
= 1 -
38=
58 58 of the paint = 5 x 8 u = 40 u
Remaining paint left = 40 u
Number of chairs that Adam can paint with the remaining paint
= 40 u ÷ 1 u
= 40
(b)
Number of doors that Adam can paint with the remaining paint
= 40 u ÷ 5 u
= 8
Answer(s): (a) 40; (b) 8