Adam has some paint.
He uses
37 of it to paint 4 chairs and 10 gates.
The amount of paint needed to paint a gate is 2 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Chairs |
Gates |
Number |
4 |
10 |
Value |
1 u |
2 u |
Total value |
4 u |
20 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 gate = 2 u
Paint needed for 4 chairs and 10 gates
= 4 x 1 u x 10 x 2 u
= 4 u + 20 u
= 24 u
37 of the paint = 24 u
17 of the paint = 24 u ÷ 3 = 8 u
Fraction of the remaining paint left
= 1 -
37=
47 47 of the paint = 4 x 8 u = 32 u
Remaining paint left = 32 u
Number of chairs that Adam can paint with the remaining paint
= 32 u ÷ 1 u
= 32
(b)
Number of gates that Adam can paint with the remaining paint
= 32 u ÷ 2 u
= 16
Answer(s): (a) 32; (b) 16