Adam has some paint.
He uses
47 of it to paint 5 gates and 9 chairs.
The amount of paint needed to paint a chair is 3 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
5 |
9 |
Value |
1 u |
3 u |
Total value |
5 u |
27 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 5 gates and 9 chairs
= 5 x 1 u x 9 x 3 u
= 5 u + 27 u
= 32 u
47 of the paint = 32 u
17 of the paint = 32 u ÷ 4 = 8 u
Fraction of the remaining paint left
= 1 -
47=
37 37 of the paint = 3 x 8 u = 24 u
Remaining paint left = 24 u
Number of gates that Adam can paint with the remaining paint
= 24 u ÷ 1 u
= 24
(b)
Number of chairs that Adam can paint with the remaining paint
= 24 u ÷ 3 u
= 8
Answer(s): (a) 24; (b) 8