Adam has some paint.
He uses
23 of it to paint 4 doors and 5 tables.
The amount of paint needed to paint a table is 4 times that of a door.
- How many doors can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Doors |
Tables |
Number |
4 |
5 |
Value |
1 u |
4 u |
Total value |
4 u |
20 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 table = 4 u
Paint needed for 4 doors and 5 tables
= 4 x 1 u x 5 x 4 u
= 4 u + 20 u
= 24 u
23 of the paint = 24 u
13 of the paint = 24 u ÷ 2 = 12 u
Fraction of the remaining paint left
= 1 -
23=
13 13 of the paint = 1 x 12 u = 12 u
Remaining paint left = 12 u
Number of doors that Adam can paint with the remaining paint
= 12 u ÷ 1 u
= 12
(b)
Number of tables that Adam can paint with the remaining paint
= 12 u ÷ 4 u
= 3
Answer(s): (a) 12; (b) 3