Adam has some paint.
He uses
49 of it to paint 4 chairs and 3 gates.
The amount of paint needed to paint a gate is 4 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Chairs |
Gates |
Number |
4 |
3 |
Value |
1 u |
4 u |
Total value |
4 u |
12 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 gate = 4 u
Paint needed for 4 chairs and 3 gates
= 4 x 1 u x 3 x 4 u
= 4 u + 12 u
= 16 u
49 of the paint = 16 u
19 of the paint = 16 u ÷ 4 = 4 u
Fraction of the remaining paint left
= 1 -
49=
59 59 of the paint = 5 x 4 u = 20 u
Remaining paint left = 20 u
Number of chairs that Adam can paint with the remaining paint
= 20 u ÷ 1 u
= 20
(b)
Number of gates that Adam can paint with the remaining paint
= 20 u ÷ 4 u
= 5
Answer(s): (a) 20; (b) 5