Adam has some paint.
He uses
79 of it to paint 8 doors and 10 chairs.
The amount of paint needed to paint a chair is 2 times that of a door.
- How many doors can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Doors |
Chairs |
Number |
8 |
10 |
Value |
1 u |
2 u |
Total value |
8 u |
20 u |
(a)
Paint needed for 1 door = 1 u
Paint needed for 1 chair = 2 u
Paint needed for 8 doors and 10 chairs
= 8 x 1 u x 10 x 2 u
= 8 u + 20 u
= 28 u
79 of the paint = 28 u
19 of the paint = 28 u ÷ 7 = 4 u
Fraction of the remaining paint left
= 1 -
79=
29 29 of the paint = 2 x 4 u = 8 u
Remaining paint left = 8 u
Number of doors that Adam can paint with the remaining paint
= 8 u ÷ 1 u
= 8
(b)
Number of chairs that Adam can paint with the remaining paint
= 8 u ÷ 2 u
= 4
Answer(s): (a) 8; (b) 4