Adam has some paint.
He uses
311 of it to paint 5 gates and 2 doors.
The amount of paint needed to paint a door is 5 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Gates |
Doors |
Number |
5 |
2 |
Value |
1 u |
5 u |
Total value |
5 u |
10 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 door = 5 u
Paint needed for 5 gates and 2 doors
= 5 x 1 u x 2 x 5 u
= 5 u + 10 u
= 15 u
311 of the paint = 15 u
111 of the paint = 15 u ÷ 3 = 5 u
Fraction of the remaining paint left
= 1 -
311=
811 811 of the paint = 8 x 5 u = 40 u
Remaining paint left = 40 u
Number of gates that Adam can paint with the remaining paint
= 40 u ÷ 1 u
= 40
(b)
Number of doors that Adam can paint with the remaining paint
= 40 u ÷ 5 u
= 8
Answer(s): (a) 40; (b) 8