Adam and Bryan have some stickers in the ratio of 6 : 5.
When Adam gives away 78 stickers,
the ratio of the stickers becomes 8 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
6 x 7 = 42 u |
5 x 7 = 35 u |
Change |
- 78 |
No change |
After |
8 x 5 = 40 u |
7 x 5 = 35 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 5 and 7.
LCM of 5 and 7 = 35
Number of stickers that Adam gives away
= 42 u - 40 u
= 2 u
2 u = 78
1 u = 78 ÷ 2 = 39
Number of stickers that they have at first
= 42 u + 35 u
= 77 u
= 77 x 39
= 3003
(b)
Number of stickers that they have in the end
= 40 u + 35 u
= 75 u
= 75 x 39
= 2925
Answer(s): (a) 3003; (b) 2925