Adam and Bryan have some stickers in the ratio of 6 : 5.
When Adam gives away 78 stickers,
the ratio of the stickers becomes 7 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
6 x 8 = 48 u |
5 x 8 = 40 u |
Change |
- 78 |
No change |
After |
7 x 5 = 35 u |
8 x 5 = 40 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 5 and 8.
LCM of 5 and 8 = 40
Number of stickers that Adam gives away
= 48 u - 35 u
= 13 u
13 u = 78
1 u = 78 ÷ 13 = 6
Number of stickers that they have at first
= 48 u + 40 u
= 88 u
= 88 x 6
= 528
(b)
Number of stickers that they have in the end
= 35 u + 40 u
= 75 u
= 75 x 6
= 450
Answer(s): (a) 528; (b) 450