Adam and Charlie have some stickers in the ratio of 7 : 6.
When Adam gives away 66 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 1 = 7 u |
6 x 1 = 6 u |
Change |
- 66 |
No change |
After |
2 x 2 = 4 u |
3 x 2 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 6 and 3.
LCM of 6 and 3 = 6
Number of stickers that Adam gives away
= 7 u - 4 u
= 3 u
3 u = 66
1 u = 66 ÷ 3 = 22
Number of stickers that they have at first
= 7 u + 6 u
= 13 u
= 13 x 22
= 286
(b)
Number of stickers that they have in the end
= 4 u + 6 u
= 10 u
= 10 x 22
= 220
Answer(s): (a) 286; (b) 220