Charlie and Adam have some stickers in the ratio of 7 : 8.
When Charlie gives away 70 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
7 x 3 = 21 u |
8 x 3 = 24 u |
Change |
- 70 |
No change |
After |
2 x 8 = 16 u |
3 x 8 = 24 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 8 and 3.
LCM of 8 and 3 = 24
Number of stickers that Charlie gives away
= 21 u - 16 u
= 5 u
5 u = 70
1 u = 70 ÷ 5 = 14
Number of stickers that they have at first
= 21 u + 24 u
= 45 u
= 45 x 14
= 630
(b)
Number of stickers that they have in the end
= 16 u + 24 u
= 40 u
= 40 x 14
= 560
Answer(s): (a) 630; (b) 560