Adam and Charlie have some stickers in the ratio of 7 : 8.
When Adam gives away 69 stickers,
the ratio of the stickers becomes 4 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 5 = 35 u |
8 x 5 = 40 u |
Change |
- 69 |
No change |
After |
4 x 8 = 32 u |
5 x 8 = 40 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 8 and 5.
LCM of 8 and 5 = 40
Number of stickers that Adam gives away
= 35 u - 32 u
= 3 u
3 u = 69
1 u = 69 ÷ 3 = 23
Number of stickers that they have at first
= 35 u + 40 u
= 75 u
= 75 x 23
= 1725
(b)
Number of stickers that they have in the end
= 32 u + 40 u
= 72 u
= 72 x 23
= 1656
Answer(s): (a) 1725; (b) 1656