Bryan and Adam have some stickers in the ratio of 5 : 2.
When Bryan gives away 75 stickers,
the ratio of the stickers becomes 7 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
5 x 2 = 10 u |
2 x 2 = 4 u |
Change |
- 75 |
No change |
After |
7 x 1 = 7 u |
4 x 1 = 4 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 2 and 4.
LCM of 2 and 4 = 4
Number of stickers that Bryan gives away
= 10 u - 7 u
= 3 u
3 u = 75
1 u = 75 ÷ 3 = 25
Number of stickers that they have at first
= 10 u + 4 u
= 14 u
= 14 x 25
= 350
(b)
Number of stickers that they have in the end
= 7 u + 4 u
= 11 u
= 11 x 25
= 275
Answer(s): (a) 350; (b) 275