Bryan and Charlie have some stickers in the ratio of 8 : 3.
When Bryan gives away 18 stickers,
the ratio of the stickers becomes 7 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
8 x 2 = 16 u |
3 x 2 = 6 u |
Change |
- 18 |
No change |
After |
7 x 1 = 7 u |
6 x 1 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 6.
LCM of 3 and 6 = 6
Number of stickers that Bryan gives away
= 16 u - 7 u
= 9 u
9 u = 18
1 u = 18 ÷ 9 = 2
Number of stickers that they have at first
= 16 u + 6 u
= 22 u
= 22 x 2
= 44
(b)
Number of stickers that they have in the end
= 7 u + 6 u
= 13 u
= 13 x 2
= 26
Answer(s): (a) 44; (b) 26