Adam and Charlie have some stickers in the ratio of 7 : 5.
When Adam gives away 31 stickers,
the ratio of the stickers becomes 5 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 8 = 56 u |
5 x 8 = 40 u |
Change |
- 31 |
No change |
After |
5 x 5 = 25 u |
8 x 5 = 40 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 5 and 8.
LCM of 5 and 8 = 40
Number of stickers that Adam gives away
= 56 u - 25 u
= 31 u
31 u = 31
1 u = 31 ÷ 31 = 1
Number of stickers that they have at first
= 56 u + 40 u
= 96 u
= 96 x 1
= 96
(b)
Number of stickers that they have in the end
= 25 u + 40 u
= 65 u
= 65 x 1
= 65
Answer(s): (a) 96; (b) 65