Bryan and Adam have some stickers in the ratio of 3 : 2.
When Bryan gives away 45 stickers,
the ratio of the stickers becomes 8 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
3 x 7 = 21 u |
2 x 7 = 14 u |
Change |
- 45 |
No change |
After |
8 x 2 = 16 u |
7 x 2 = 14 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 2 and 7.
LCM of 2 and 7 = 14
Number of stickers that Bryan gives away
= 21 u - 16 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of stickers that they have at first
= 21 u + 14 u
= 35 u
= 35 x 9
= 315
(b)
Number of stickers that they have in the end
= 16 u + 14 u
= 30 u
= 30 x 9
= 270
Answer(s): (a) 315; (b) 270