Adam and Charlie have some stickers in the ratio of 7 : 3.
When Adam gives away 66 stickers,
the ratio of the stickers becomes 8 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 5 = 35 u |
3 x 5 = 15 u |
Change |
- 66 |
No change |
After |
8 x 3 = 24 u |
5 x 3 = 15 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of stickers that Adam gives away
= 35 u - 24 u
= 11 u
11 u = 66
1 u = 66 ÷ 11 = 6
Number of stickers that they have at first
= 35 u + 15 u
= 50 u
= 50 x 6
= 300
(b)
Number of stickers that they have in the end
= 24 u + 15 u
= 39 u
= 39 x 6
= 234
Answer(s): (a) 300; (b) 234