Bryan and Charlie have some stickers in the ratio of 3 : 4.
When Bryan gives away 65 stickers,
the ratio of the stickers becomes 4 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
3 x 7 = 21 u |
4 x 7 = 28 u |
Change |
- 65 |
No change |
After |
4 x 4 = 16 u |
7 x 4 = 28 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 4 and 7.
LCM of 4 and 7 = 28
Number of stickers that Bryan gives away
= 21 u - 16 u
= 5 u
5 u = 65
1 u = 65 ÷ 5 = 13
Number of stickers that they have at first
= 21 u + 28 u
= 49 u
= 49 x 13
= 637
(b)
Number of stickers that they have in the end
= 16 u + 28 u
= 44 u
= 44 x 13
= 572
Answer(s): (a) 637; (b) 572