Adam and Charlie have some stickers in the ratio of 2 : 3.
When Adam gives away 88 stickers,
the ratio of the stickers becomes 4 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
2 x 7 = 14 u |
3 x 7 = 21 u |
Change |
- 88 |
No change |
After |
4 x 3 = 12 u |
7 x 3 = 21 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 7.
LCM of 3 and 7 = 21
Number of stickers that Adam gives away
= 14 u - 12 u
= 2 u
2 u = 88
1 u = 88 ÷ 2 = 44
Number of stickers that they have at first
= 14 u + 21 u
= 35 u
= 35 x 44
= 1540
(b)
Number of stickers that they have in the end
= 12 u + 21 u
= 33 u
= 33 x 44
= 1452
Answer(s): (a) 1540; (b) 1452