Adam and Bryan have some stickers in the ratio of 5 : 2.
When Adam gives away 40 stickers,
the ratio of the stickers becomes 5 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
5 x 3 = 15 u |
2 x 3 = 6 u |
Change |
- 40 |
No change |
After |
5 x 2 = 10 u |
3 x 2 = 6 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of stickers that Adam gives away
= 15 u - 10 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of stickers that they have at first
= 15 u + 6 u
= 21 u
= 21 x 8
= 168
(b)
Number of stickers that they have in the end
= 10 u + 6 u
= 16 u
= 16 x 8
= 128
Answer(s): (a) 168; (b) 128