Charlie and Adam have some stickers in the ratio of 7 : 3.
When Charlie gives away 98 stickers,
the ratio of the stickers becomes 7 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
7 x 4 = 28 u |
3 x 4 = 12 u |
Change |
- 98 |
No change |
After |
7 x 3 = 21 u |
4 x 3 = 12 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 3 and 4.
LCM of 3 and 4 = 12
Number of stickers that Charlie gives away
= 28 u - 21 u
= 7 u
7 u = 98
1 u = 98 ÷ 7 = 14
Number of stickers that they have at first
= 28 u + 12 u
= 40 u
= 40 x 14
= 560
(b)
Number of stickers that they have in the end
= 21 u + 12 u
= 33 u
= 33 x 14
= 462
Answer(s): (a) 560; (b) 462