Bryan and Adam have some stickers in the ratio of 8 : 3.
When Bryan gives away 44 stickers,
the ratio of the stickers becomes 4 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
8 x 7 = 56 u |
3 x 7 = 21 u |
Change |
- 44 |
No change |
After |
4 x 3 = 12 u |
7 x 3 = 21 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 3 and 7.
LCM of 3 and 7 = 21
Number of stickers that Bryan gives away
= 56 u - 12 u
= 44 u
44 u = 44
1 u = 44 ÷ 44 = 1
Number of stickers that they have at first
= 56 u + 21 u
= 77 u
= 77 x 1
= 77
(b)
Number of stickers that they have in the end
= 12 u + 21 u
= 33 u
= 33 x 1
= 33
Answer(s): (a) 77; (b) 33