Bryan and Charlie have some stickers in the ratio of 5 : 3.
When Bryan gives away 88 stickers,
the ratio of the stickers becomes 8 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
5 x 7 = 35 u |
3 x 7 = 21 u |
Change |
- 88 |
No change |
After |
8 x 3 = 24 u |
7 x 3 = 21 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 7.
LCM of 3 and 7 = 21
Number of stickers that Bryan gives away
= 35 u - 24 u
= 11 u
11 u = 88
1 u = 88 ÷ 11 = 8
Number of stickers that they have at first
= 35 u + 21 u
= 56 u
= 56 x 8
= 448
(b)
Number of stickers that they have in the end
= 24 u + 21 u
= 45 u
= 45 x 8
= 360
Answer(s): (a) 448; (b) 360