Bryan and Charlie have some stickers in the ratio of 7 : 4.
When Bryan gives away 100 stickers,
the ratio of the stickers becomes 4 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
7 x 3 = 21 u |
4 x 3 = 12 u |
Change |
- 100 |
No change |
After |
4 x 4 = 16 u |
3 x 4 = 12 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 4 and 3.
LCM of 4 and 3 = 12
Number of stickers that Bryan gives away
= 21 u - 16 u
= 5 u
5 u = 100
1 u = 100 ÷ 5 = 20
Number of stickers that they have at first
= 21 u + 12 u
= 33 u
= 33 x 20
= 660
(b)
Number of stickers that they have in the end
= 16 u + 12 u
= 28 u
= 28 x 20
= 560
Answer(s): (a) 660; (b) 560