Bryan and Charlie have some stickers in the ratio of 7 : 3.
When Bryan gives away 50 stickers,
the ratio of the stickers becomes 3 : 2.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
7 x 2 = 14 u |
3 x 2 = 6 u |
Change |
- 50 |
No change |
After |
3 x 3 = 9 u |
2 x 3 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 2.
LCM of 3 and 2 = 6
Number of stickers that Bryan gives away
= 14 u - 9 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of stickers that they have at first
= 14 u + 6 u
= 20 u
= 20 x 10
= 200
(b)
Number of stickers that they have in the end
= 9 u + 6 u
= 15 u
= 15 x 10
= 150
Answer(s): (a) 200; (b) 150