Bryan and Adam have some stickers in the ratio of 4 : 5.
When Bryan gives away 20 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
4 x 3 = 12 u |
5 x 3 = 15 u |
Change |
- 20 |
No change |
After |
2 x 5 = 10 u |
3 x 5 = 15 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 5 and 3.
LCM of 5 and 3 = 15
Number of stickers that Bryan gives away
= 12 u - 10 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that they have at first
= 12 u + 15 u
= 27 u
= 27 x 10
= 270
(b)
Number of stickers that they have in the end
= 10 u + 15 u
= 25 u
= 25 x 10
= 250
Answer(s): (a) 270; (b) 250