Bryan and Adam have some stickers in the ratio of 7 : 8.
When Bryan gives away 68 stickers,
the ratio of the stickers becomes 4 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
7 x 7 = 49 u |
8 x 7 = 56 u |
Change |
- 68 |
No change |
After |
4 x 8 = 32 u |
7 x 8 = 56 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 8 and 7.
LCM of 8 and 7 = 56
Number of stickers that Bryan gives away
= 49 u - 32 u
= 17 u
17 u = 68
1 u = 68 ÷ 17 = 4
Number of stickers that they have at first
= 49 u + 56 u
= 105 u
= 105 x 4
= 420
(b)
Number of stickers that they have in the end
= 32 u + 56 u
= 88 u
= 88 x 4
= 352
Answer(s): (a) 420; (b) 352